A dipole of dipole moment p is kept at the center of a ring of radius R and charge Q. The dipole moment has direction along the axis of the ring. The resultant force on the ring due to the dipole is:

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A dipole of dipole moment p is kept at the center of a ring of radius R and charge Q. The dipole moment has direction along the axis of the ring. The resultant force on the ring due to the dipole is:

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$\frac{k P Q}{R^{3}}$ , only if the charge is uniformly distributed on the ring.

$\frac{k P Q}{R^{3}}$

Zero

$\frac{2 k P Q}{R^{3}}$

answer is B.

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Detailed Solution

Electric field at each point on the surface of ring due to dipole is $E = \frac{kp}{R^{3}}$ in direction opposite to the dipole moment.

Hence, net force on ring is $F = QE = \frac{kpQ}{R^{3}} .$

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