Q.

A direct current of 4 A and an alternating current of peak value 4 A flow through resistance of 3 Ω and 2 Ω respectively. The ratio of heat produced in the two resistances in same interval of time will be :

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a

3 : 1

b

3 : 2

c

3 : 4

d

4 : 3

answer is B.

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Detailed Solution

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H1=i2R1t  H2=irms2R2tirms=i02H1=16(3)t H2=i022R2t                        H2=16tH1 : H2=3 : 1

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