Q.

A disc of mass m, radius R is set into rolling with angular velocity ω, up on a rough inclined plane of inclination 300 to the horizontal and is in rolling motion always. The distance it will move up on the inclined plane will be xR2ω2g.

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answer is 1.5.

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Detailed Solution

12m(Rω)2+12mR22ω2=mghh=34R2ω2g                          =hsin30=32R2ω2g         

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