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Q.

A disc of radius 2m and mass 100 kg rolls on a horizontal floor. Its centre of mass has speed of 20 cm/s. How much work is needed to stop it?

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a

2J

b

3J

c

30kJ

d

1J

answer is C.

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Detailed Solution

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Work required = change in kinetic energy
Final KE = 0


Initial  KE=12mv2+12Iω2=34mv2

=34×100×20×10−22=3J;|ΔKE|=3J
 

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