A disc rotating about its axis with angular speed  is placed gently (without any translational push) on a perfectly frictionless horizontal table. The radius of the disc is R. Let v_A, v_B and v_C be the magnitude of linear velocities of the points A, B and C on the disc as shown. Then

Due to the absence of frictional force, no torque is acting on the disc, also no horizontal external force is acting on the disc. Therefore centre of mass of the disc remains stationary and its angular velocity remains unchanged. Now tangential speed v = ${\omega }_0$r. since$r_A=r_B=R and r_c=\frac{R}{2}$  option (4) is correct.