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Q.

A diverging meniscus lens of 1.5 refractive index has concave surfaces of radii 3 and 4 cm. The position of image if an object is placed 12 cm infront of the lens is

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a

-8 cm

b

24 cm

c

-24 cm

d

8 cm

answer is B.

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Detailed Solution

$\frac{1}{f} = (μ - 1) (\frac{1}{R_{1}} - \frac{1}{R_{2}}); \frac{1}{f} = \frac{1}{v} - \frac{1}{u}$

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