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Q.

A diverging meniscus lens of radii of curvatures 25 cm and 50 cm has a refractive index 1.5. Its focal length is (in cm)

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a

– 50

b

50

c

–100

d

100

answer is B.

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Detailed Solution

$\frac{1}{f} = (μ - 1) (\frac{1}{R_{1}} - \frac{1}{R_{2}})$

$= \frac{1}{2} (\frac{1}{- 25} - \frac{1}{- 50})$

$f = - 100 c m$

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A diverging meniscus lens of radii of curvatures 25 cm and 50 cm has a refractive index 1.5. Its focal length is (in cm)