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A DNA model was constructed using the scale relation as 2 cm : 0.0000001 mm. If the model of the DNA chain is 17 cm, what is the length of the original chain?

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0.00000085mm

0.085mm

0.0085mm

0.00085mm

answer is A.

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Detailed Solution

Given, the DNA model was constructed using the scale relation as 2 cm : 0.0000001 mm.
So,

\frac{DNA model}{Actual model} = \frac{2 cm}{0.0000001 mm}

= \frac{20 mm}{0.0000001 mm}

The model of the DNA chain is 17 cm.
So,

\frac{DNA model}{Actual model} = \frac{17}{Actual nodel}

.
=>

\frac{17}{Actual nodel}

= \frac{20}{0.0000001}

Actual model =

\frac{17}{20} \times 0.0000001

= 0.00000085mm
Hence, the actual model length is 0.00000085 mm.
Hence, option 1 is correct.

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