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Q.

A dot makes a turn in a circle 5 times in a second. The radius of the circle is 5 cm and the dot moves uniformly. What is the acceleration of the dot in m/s²

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a

$\frac{π^{2}}{125}$

b

$5 π^{2}$

c

$2 π^{2}$

d

Zero

answer is D.

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Detailed Solution

Total distance= $\frac{10 π \times 5}{100} = \frac{π}{2}$

Time= 1 s

speed= $\frac{π}{2}$

Acceleration= $\frac{v^{2}}{R} = \frac{π^{2} \times 100}{4 \times 5} = 5 π^{2}$

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