A dot mark of a lead pencil has mass of $6 μ g$ of carbon. Thus number of carbon atoms in one dot mark is_____

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$6.02 \times 10^{20}$

$3.01 \times 10^{17}$

$3.01 \times 10^{20}$

$6.02 \times 10^{17}$

answer is A.

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Detailed Solution

$w t = 6 \times 10^{- 6} g r a m$
Number of carbon atoms= $\frac{6 \times 10^{- 6}}{\frac{12}{N_{A}}}$
$= \frac{6 \times 10^{- 6} N_{A}}{12} = 3 \times 10^{17}$

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