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A double convex lens has radii of curvature of 2 m and 3m. What should be the refractive index of the medium so that the focal length of the lens is 100 cm ?

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1.2

2.2

2.4

1.4

answer is B.

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Detailed Solution

$\frac{1}{f} = (μ - 1) (\frac{1}{R_{1}} + \frac{1}{R_{2}})$

$\frac{1}{1} = (μ - 1) (\frac{1}{2} + \frac{1}{3})$

$μ - 1 = \frac{6}{5}$

$μ = \frac{6}{5} + 1 = \frac{11}{5} = 2.2$

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