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Q.

A drop of a solution (volume = 0.05 ml) contains 6 5 10-7 mol of H+. If rate of disappearance  of H+is how long will it take for the H+in the drop to disappear?

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a

2.0 × 10−2s

b

8.0  × 10−8s

c

6.0 ×10−6s

d

2.0 5 10− 8s

answer is B.

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Detailed Solution

[H+] = 6 ×10-70.05 × 10-3 = 1.2 × 10-2M

Rate r = ΔXΔt; Δt = ΔXr = 1.2 × 10-2M6 × 105 Ms-1

∴ T = 2 × 10-8s

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