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A drop of radius 1mm is sprayed into 1000 droplets of same size. If surface tension of the liquid is 40 dyne (cm-1), the amount of work done in the process is

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a
4.53erg
b
4.53J
c
4.53×10-6J
d
9.06×10-6J

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detailed solution

Correct option is C

Given,

n=1000, T=40dyne/cm

R=1mm=10-3m & R=n13r

we know that,

Work done = difference in surface area ×surface tension

W= 4π(nr2R2)T=4πR2T(n131)

W=4(3.14)(103)2(40)×10-3[(1000)131]=4.53×10-6J

Hence the correct answer is 4.53×10-6J.

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