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Q.

A drunkard is walking along a straight road. He takes 5 steps forward and 3 steps backward and so on. Each step is 1m long and takes 1s. There is a pit on the road 11m away from the starting point. The drunkard will fall into the pit after 

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a

31s

b

21s

c

37s

d

29s

answer is B.

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Detailed Solution

For last 5 steps no back ward motion
Time taken for last 5m = 5 sec
remaining distance =11–5 m

With forward and backward motion such that 2m takes  8s
So for 6 m time = 6/2 x 8 = 24sec
Total time = 24 + 5 = 29 sec.

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