A drunkard takes a step of 1m in 1s. He takes 5 steps forward and 3 steps backward and so on. The time taken by him to fall in a pit of 13m away from the start is:

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26s

31s

37s

41s

answer is C.

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Detailed Solution

Concept: As said, it takes the inebriated person one second to move one metre.
He takes 5 steps ahead and 3 steps forward, so we can ignore the final 5 steps of the inebriated man and figure out how long it took him to reach the remaining distance. The time the inebriated person took to get there and take the final five steps can then be added. We will then have the time it took him to fall one metre into the hole.
The guy moves 13 metres away from the pit and moves 5 steps forward and 3 steps back. Each step is 1 metre long.
5m⟶2m
7m⟶4m
9m⟶6m
11m⟶8m
13m
Each stride takes 8 seconds, 5 of which are spent moving forward and 3 backward.
Now, it takes him 32 seconds to cover 8 metres.
He covers the 13 m distance in 32 + 5 = 37 seconds.
Hence, the correct option is 3 .

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