A drunkard walking along a road takes 5 steps forward and 3 steps backward, and so on. Each step is 1m long and takes 1s. There is a pit on the road 11m away from the starting point. The drunkard fall into the pit after:

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29 steps

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31 steps

answer is A.

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Detailed Solution

Concept- The above question is calculated with a number line for the sake of clarity. The distance between each point on the line is 1km. There is a pit at the 11th point.
Given he takes 5 steps forward and 3 steps backward. Each step is 1m long and lasts 1 second. Now let's make a number line.
seo

In the above two steps he reached point 2. But he moved

steps. Therefore, the total distance he traveled, One step takes 1 second, so 8 steps takes 8 seconds. In other words, it can be said that it travels 2 km in 8 seconds. Move from point 2 in the same way. That is, 5 in the front and 3 in the back.
seo

Now, person is on 4th point In another 8 seconds, it will cover another 2 km. Now he is at point 6. That is, he ran a total of 6km in 16 + 8 = 24 seconds. However, after 5 steps from point 6, he falls into the pit and cannot retreat. So in the next five steps he took 5 seconds. Or, the total time

Hence, the correct answer is option (1)

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