A dry gas occupied $136.5 {cm}^{3}$ at STP. If the same mass of the gas is collected over water at 27 °C at a total pressure of 725 Torr, what volume does it occupy? The vapour pressure of water at 27 °C is 25 Torr.

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$157.3 {cm}^{3}$

$159.2 {cm}^{3}$

$162.9 {cm}^{3}$

$160.9 cm$

answer is B.

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Detailed Solution

$V_{2} = V_{1} (\frac{T_{2}}{p_{2}}) (\frac{p_{1}}{T_{1}}) = (136.5 {cm}^{3}) (\frac{300 K}{(725 - 25) Torr}) (\frac{760 Torr}{273 K}) = 162.9 {cm}^{3}$

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