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A dry gas occupies 125 cm³ at STP. If the same gas is collected over water at 27 ^oC at a total pressure of 750 Torr, the volume occupied by the gas is (Given: aqueous tension of water at 27 ^oC is 25 Torr.)

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125 cm³

115.0 cm³

155 cm³

144.0 cm³

answer is A.

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Detailed Solution

The pressure of dry gas in the gas collected over water $p_{2} = p_{mixture} - p_{water} = (750 - 25) Torr = 725 Torr$

Now, using ideal gas equation $(p_{2} V_{2} / T_{2} = p_{1} V_{1} / T_{1})$ , we get

$V_{2} = (\frac{p_{1}}{p_{2}}) (\frac{T_{2}}{T_{1}}) V_{1} = (\frac{760}{725}) (\frac{300}{273}) (125 {cm}^{3}) = 144.0 {cm}^{3}$

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