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Q.

A duster weighs 0.7N. It is pressed against a vertical board with a horizontal force of 11N. If the co-efficient of friction is 0.5, the  minimum force that must be applied on the block parallel to surface to move it upwards is

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a

7N

b

6.2N

c

0.4N

d

0.7

answer is C.

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Detailed Solution

FR=μF+mg=(0.5×11)+0.7=5.5+0.7=6.2 N

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