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A dynamometer D is attached to two blocks of masses 6 kg and 4 kg. Forces of 20 N and 10N are applied on the blocks as shown in Fig. The dynamometer reads

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6 N

20 N

10 N

14 N

answer is D.

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Detailed Solution

20 - D = 6 a

$\underline{- 10 + D = 4 a}$

$10 = 10 a$

$a = 1 {ms}^{- 2}$

$D - 10 = 4 a$

$D - 10 = 4$

$D = 14 N$

The dynometer reads 14 N

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