A dynamometer D is attached to two blocks of masses 6 kg and 4 kg. Forces of 20 N and 10N are applied on the blocks as shown in Fig. The dynamometer reads

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10N

20N

14N

answer is D.

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Detailed Solution

Let force in the spring = F at maximum extension of
the spring
$\begin{array}{l} a_{1} = a_{2} \\ \frac{F_{1} - F}{m_{1}} = \frac{F - F_{2}}{m_{2}} \Rightarrow F = \frac{F_{1} m_{2} + F_{2} m_{1}}{m_{1} + m_{2}} \\ F = \frac{20 \times 4 + 10 \times 6}{6 + 4} = 14 N \end{array}$

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