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A faculty of KOTA Institute who has five classes per day, after taking the fourth class and before going for next class, drinks 500 ml of 9 % ( w/v) glucose solution. The number of glucose molecules taken by him is $= Q x 10^{23}^{}$ . Find the value of Q. $(N_{A} = 6.0 \times 10^{23})$

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6.5

1.5

4.5

answer is D.

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Detailed Solution

We have,

$500 \times \frac{9}{100} \times \frac{1}{180} \times 6 \times 10^{23} = Q \times 10^{23}$

On comparing and solving get the value of Q as 1.5.

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