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Q.

A fair coin is tossed 100 times. Then the probability of getting tails an odd number of times is

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a

$\frac{1}{2}$

b

$\frac{1}{4}$

c

$\frac{1}{8}$

d

$\frac{3}{8}$

answer is A.

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Detailed Solution

Required probability $= \frac{{}^{100}C_{1} + {}^{100}C_{3} + \dots + {}^{100}C_{99}}{2^{100}} = \frac{2^{99}}{2^{100}} = \frac{1}{2}$

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