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A fair die is tossed repeatedly. Mr A wins if it is 1 or 2. Mr B wins if its is 3, 4, 5 or 6. The probability that A wins if the die is tossed indefinitely is:

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Detailed Solution

Let event S → A is getting 1 or 2 vent F → B is getting 3, 4, 5, 6
P(S) = P(1 or 2) = 1/3
P(F) = P(3 or 4 or 5 or 6) = 2/3
P(A wins) = P[SS or SFSS or SFS]
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P(A winning) =

Hence option (A) is correct.

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