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A far sighted person cannot focus distinct y objects closer than 120cm. the lens that will permit him to read from a distance of 40cm will have a focal length.

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60cm

-60cm

30cm

-30cm

answer is C.

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Detailed Solution

$ϑ = 40 u = 120 cm \begin{array}{l} \frac{1}{f} = \frac{1}{v} - \frac{1}{u} = \frac{1}{40} - \frac{1}{120} = \frac{3 - 1}{120} = \frac{2}{120} \\ f = 60 cm \end{array}$

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