A farmer moves along the boundary of a square field of side 10 m in 40 s. The magnitude of displacement of the farmer at the farmer at the end of 2 minutes 20 seconds from his initial position [[1]]m.

Determine the point on the square that represents the farmer's ultimate location by calculating the net distance the farmer has traveled using the supplied values. The net displacement is the length of the line immediately connecting the farmer's beginning and end positions.

Given the side of the square$=10 \mathrm{m}$, thus perimeter $P=40 \mathrm{m}$
Time required to traverse the perimeter of $40 \mathrm{m}=40 \mathrm{s}$
Consequently, the farmer travels a distance of 1 second of$1 \mathrm{m}$
Now the farmer's travel distance in $2 \min 20$ seconds $=1\times 140=140 \mathrm{m}$
The farmer now completes 140 rotations in total to cross the distance.
meters $=\frac{\text{ total distance }}{\text{ perimeter }}=3.5$
The farmer is now, let's say, at point B from the origin O.
Hence the relocation $\mathrm{s}=\sqrt{{10}^2+{10}^2}$ through the Pythagorean theorem.
$\mathrm{s}=10\sqrt{2}=14.14 \mathrm{m}$

Hence, the correct answer is option 14.14.