A father divides his property among his 3 sons such that the eldest son's share is double the second son's share and the share of the second son is triple the third son's share. If the second son gets Rs.4000 more than the third, find the value of the total property.

Suppose share of eldest sons = z
Share of second sons = y
Share of third sons = x 
Here, the eldest son's share = 2 x second son's share. 

So,
$\Rightarrow 2\mathrm{y}=\mathrm{z}$ 

The share of the second son = 3 x third son's share.
$\Rightarrow \mathrm{y}=3\mathrm{x}$ 

Now, second son gets Rs. 4000 more than 3^rd son, so
$\mathrm{y}=\mathrm{x}+4000$ 

$3\mathrm{x}=\mathrm{x}+4000\mathrm{ }$         (since, y =3x)
$2\mathrm{x}=4000\mathrm{ }$
$\mathrm{x}=2000\mathrm{ }$ 

So, the third son's share, $\mathrm{x}=\mathit{R}\mathit{s}\mathbf{.}\mathbf{ }\mathbf{2000}$
Now, second son's share
$\mathrm{y}=3\mathrm{x}$
$\mathrm{y}=\mathit{R}\mathit{s}\mathbf{.}\mathbf{ }\mathbf{6000}$
The share of the eldest son,
$\mathrm{z}=2\mathrm{y}$
$\mathrm{z}=\mathit{R}\mathit{s}\mathbf{.}\mathbf{ }\mathbf{12000}$
So, the total money,
$=\mathrm{x}+\mathrm{y}+\mathrm{z}$
$=2000+6000+12000$
$=\mathrm{Rs}. 20000\mathrm{ }$ 

Hence, the total value of the property = Rs. 20000.