A father purchases dresses for his three daughters.The dresses are of the same color but of different sizes .The dress is kept in a dark room .What is the probability that all the three will not choose their own dress?

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answer is B.

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Detailed Solution

Here,
For 1st girl, the total outcomes = 3 (Because there is total 3 dresses in the room) For her, Favourable outcomes = no. of wrong dresses = 2
So, Probability of choosing wrong dress for her = 2
3
Now, There are 2 dresses left for the 2nd girl. So, the total outcomes = 2
And Favourable outcomes = no. of wrong dresses = 1
So, Probability of choosing wrong dress for her = 1
2
Similarly,
for 3rd girl, Probability of choosing wrong dress = 1
Therefore, Probability that all the 3 will not choose their own dress = 2 × 1 × 1 = 1
3 2 3

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