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A fax message is to be sent from Delhi to Washington via a geostationary satellite. If the minimum time delay between the dispatch and its getting received , is $y \times 10^{- 2}$ sec, then y is
(Height of geostationary satellite = 36,000 km)

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answer is 24.

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Detailed Solution

$Minimum distance = S = 2 h = 2 \times 36000 km = 72 \times 10^{6} m$

$Minimum time delay = t = \frac{S}{C} = \frac{72 \times 10^{6}}{3 \times 10^{8}} = 24 \times 10^{- 2} \sec$

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