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Q.

A FCC lattice has lattice parameter a = 400 pm. Calculate the molar volume of the lattice including all the empty space :

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a

96 mL

b

9.6 mL

c

10.8 mL

d

8.6 mL

answer is D.

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Detailed Solution

Volume of unit cell $= 400^{3} = 64 \times 10^{- 24} {cm}^{3}$

Volume of $N_{A}$ unit cell $= 64 \times 6 \times 10^{23} \times 10^{- 24} {cm}^{3} = \frac{384}{10} = 38.4 {cm}^{3}$

Molar volume $= \frac{38.4}{4} = 9.6 mL$ .

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