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A feed store sells two varieties of birdseed: Brand A, which is 40% millet and 60% sunflower, and Brand B, which is 65% millet and 35% sunflower. If a customer purchases a mix of the two types of birdseed that is 50% millet, then what percent of mix is Brand A?

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40%

55%

60%

45%

answer is C.

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Detailed Solution

Let the weight of the mixture = 1 unit
Let the weight of Brand A in the mixture =

x

unit
Then the weight of Brand B in the mixture =

1 - x

unit
Brand A has 40% millet, Brand B has 65% millet, and the mixture has 50% millet, therefore we will get the equation as,

\Rightarrow

40%

x

+ 65%

(1 - x)

= 50%

\Rightarrow

0.40

x

+ 0.65

(1 - x)

= 0.50

\Rightarrow

0.40

x

+ 0.65 - 0.65

x

= 0.50

\Rightarrow

-0.25

x

= -0.15

\Rightarrow

x

\frac{0.15}{0.25}

\Rightarrow

x

= 0.6
To find the percentage,

\Rightarrow

x

= 0.6

\times

100 = 60%
Hence, Brand A is 60% of the mix

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