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A field is 70 m long and 40 m broad. In the corner of the field, a pit which is 10 m long, 8 m broad and 5 m deep, has been dug out. The earth taken out of it is evenly spread over the remaining part of the field. Find the rise in the level of the field.

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3.147 m

0.147 m

2.147 m

1.147 m

answer is B.

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Detailed Solution

It is given a field is 70 m long and 40 m broad.
Let the level of the field rise by h m.
Volume of the field =Area of the remaining field

× h

⇒ [(70 × 40)

- 10(8)]

× h

⇒ (2800 − 80) × h

⇒ 2720 h m 3

It is given a pit which is 10 m long, 8 m broad and 5 m deep, has been dug out.
Volume of the earth taken out is

⇒

×

×

⇒ 400 m 3

Volume of the earth taken out = volume of the field

⇒

400=

2720 ×

⇒

h ≈ 0.147

m
The rise in the level of the field is 0.147 m.
Therefore, the correct option is 2.

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