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A field is in the form of a rectangle of length 18 m and width 15 m. A pit, 7.5 m long, 6 m broad and 0.8 m deep, is dug in a corner of the field and the earth taken out is spread over the remaining area of the field. Find out the extent to which the level of the field has been raised.

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0.15 m

0.17 m

0.18 m

0.16 m

answer is D.

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Detailed Solution

The dimensions of the pit are 7.5 m long, 6 m broad and 0.8 m deep.
So, volume of the pit

= 7.5

× 6

× 0.8

m
Let the height of the field raised be

h

.
The volume of a cuboid whose length, breadth and height are l, b and h is given by,

V = l × b × h

.
The dimensions of the rectangular field are length 18 m and width 15 m.
Volume of the field

= (18 m × 15 m) − (7.5 m × 6 m) h

⇒ 270 − 45 h

⇒ 225 h

Volume of the pit = volume of the field raised.

⇒

225

× h = 7.5 × 6 × 0.8

⇒ 225 h = 36

⇒

h = 0.16

m
Hence, the height of the field raised is 0.16 m.
Therefore, the correct option is 4.

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