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A filament bulb (500 W, 100 V) is to be used in a 230 V main supply. When a resistance R is connected in series, it works perfectly and the bulb consumes 500 W. The value of R is :-

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$46 Ω$

$26 Ω$

$13 Ω$

$230 Ω$

answer is A.

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Detailed Solution

$\begin{array}{l} R_{b u l b} = \frac{V^{2}}{P} \\ \frac{R}{R_{b u l b}} = \frac{130}{100} \end{array}$

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