A filament bulb $500W,100V$ is used in a $230V$ main supply. When a resistance $R$ is connected in series, it works perfectly and the bulb consumes 500W. The value of R is given a

Ohm's law is a law that states that 'the voltage across a resistor is directly proportional to the current flowing through the resistance. Ohm's law is named after the German physicist Georg Ohm (1789 -1854). This is a simple equation. Ohm's law is used to conclude the relationship between current, voltage, and resistance. The ohm is described as an electrical resistance among two points of a conductor when a certain potential difference of one volt which is applied to these points generates a current of one ampere in a current-carrying conductor. Here as already mentioned,

$R=r$

The maximum power generated is given as,

$Pmax.=\frac{E^2}{4r}$

And also power can be written as,

$P=V\times I$

Therefore the current can found by rearranging,

$I= \frac{P}{V}=\frac{500}{100}=5A$

Now according to ohm's law,

$V = I\times R = (230 – 100) = 5R$

Therefore after the calculation, the value of resistance is given as

$R = 26\Omega$

Hence the correct answer in the option is given as option A.