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Q.

A film of water is formed between two straight parallel wires, each 10 cm long and at a separation of 0.5 cm. The work that must be done to increase the separation between the wires by 1 mm is (surface tension of water =7.0×10-2 Nm-1)

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a

7.0 x 10-5 N 

b

1.4 x 10-5 N

c

 l .4 x 10-7 N 

d

7.0 x 10-7 N

answer is B.

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Detailed Solution

F = 2 σl.  Work done is W.= FS                                = 2 σlS                                = 2 × 7.0× 10-2 × 0.1× 0.001                                = 1.4× 10-5 N,

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