A film of water is formed between two straight parallel wires of length 10cm each separated by 0.5 cm. If their separation is increased by 2 mm while still maintaining their parallelism how much work will have to be done of water. Surface tension of water = 7.2×10−2Nm−1

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A film of water is formed between two straight parallel wires of length 10cm each separated by 0.5 cm. If their separation is increased by 2 mm while still maintaining their parallelism how much work will have to be done of water. Surface tension of water = $7.2 \times 10^{- 2} N m^{- 1}$

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$2.88 \times 10^{- 5} J$

$5.76 \times 10^{- 5} J$

$7.22 \times 10^{- 6} J$

$1.44 \times 10^{- 5} J$

answer is C.

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Detailed Solution

$W = T . Δ A = T .21 Δ x \begin{array}{l} = 7.2 \times 10^{- 2} \times 2 \times 10 \times 10^{- 2} \times 2 \times 10^{- 3} \\ = 28.8 \times 10^{- 6} = 2.88 \times 10^{- 5} J \end{array}$