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Q.

A fireman wants to slide down a rope. The breaking load for the rope is 3/4th of the weight of the man. With what minimum acceleration should the fireman slide down? Acceleration due to gravity is g.

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a

g/4

b

g/2

c

3g/4

d

zero

answer is B.

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Detailed Solution

$T = \frac{3}{4} mg; m (g - a) = \frac{3}{4} mg$

$a = g - \frac{3}{4} g$

$∴ a = g / 4$

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