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Q.

A first order reaction has a rate constant $1.15 \times 10^{- 3} \sec^{- 1}$ . How long will 5 gram of this reactant take to reduce to 3 gram?

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a

400 sec

b

444 sec

c

500 sec

d

532 sec

answer is B.

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Detailed Solution

$\begin{array}{l} K = \frac{2.303}{t} \log \frac{5}{3} \\ t = \frac{2.303}{K} \log \frac{5}{3} = 444 \sec \end{array}$

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