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Q.

A fish looking up through the water sees the outside world contained in a circular horizon. If the refractive index of water is 4/3 and the fish is 12 cm below the surface, the radius of this circle in cm is

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a

$36 \sqrt{7}$

b

$4 \sqrt{5}$

c

$36 \sqrt{5}$

d

$36 / \sqrt{7}$

answer is B.

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Detailed Solution

$r = \frac{h}{\sqrt{μ^{2} - 1}} = \frac{36}{\sqrt{7}}$

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