A five digit number divisible by 3 is to be formed using the numerals 0,1,2,3,4 and 5 without repetition. The total number of ways this can be done is

We 1^st  note that a number is dividible by 3 if the sum of the digits is divisible by 3. Hence from the given digits the eligible candidates are 0,1,2,4,5 or 1,2,3,4,5. Number of arrangements in
$\therefore$ Total number of desired numbers is 96+120=216