A five digit number divisible by 3 is to be formed using the digits 0, 1, 2, 3, 4 and 5 without repetition. The total number of ways, this can be done is 

As $0+1+2+3+4+5=15$, for a five digit number to be divisible by 3 either do not use 0 or 3. 

When 0 is not used, the number of such numbers is 5! and when 3 is not used, 

the number of such numbers is $5! -4!$

$\therefore$Required number of ways $=5!+(5!-4!)=216$