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A flash light lamp is marked 3.5V and 0.28A. The filament temperature is 425°C. The filament resistance at 0°C is 4 $Ω$ . Then, the temperature coefficient of resistance of the material of the filament is

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$5 \times 10^{- 3} / K$

$3.5 \times 10^{- 3} / K$

$8.5 \times 10^{- 3} / K$

$0.5 \times 10^{- 3} / K$

answer is D.

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Detailed Solution

$\begin{array}{l} R_{t} = \frac{V}{I} = \frac{3 .5}{0 .28} = 12 .5 Ω; α = \frac{R_{t} - R_{0}}{R_{0} t} \\ α = \frac{12 .5 - 4}{4 \times 425} = \frac{8 .5}{4 \times 425} = \frac{8 .5}{1700} = 5 \times 10^{- 3} \end{array}$

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