A flask containing 2.0 moles of ‘He’ gas at 1.0 atm and 300 K is connected to another flask containing $N_{2} (g)$ at the same temperature and pressure by a narrow tube of negligible volume, with a stop cock. Volume of the nitrogen flask is three times to volume of ‘He’ flask. Now the ‘He’ – flask is placed in a
thermostat at 200K and $N_{2}$ flask in another thermostat at 400K and stop cock is opened and kept for sometime to attain constant pressure. Final pressure inside of the flasks is approximately

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0.66 atm

1.06 atm

2.1 atm

1.5 atm

answer is D.

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Detailed Solution

$\frac{n_{H c}}{n_{N_{2}}} = \frac{1}{3} \times \frac{400}{200} = 2 / 3,$ Also $n_{H_{c}} + n_{N_{2}} = 8,$ No of moles in first vessel and second vessel respectively are $= \frac{16}{5}, \frac{24}{5} \frac{1}{300 \times 2} = \frac{p}{200 \times \frac{16}{5}}, P = 1.066 a t m$