A flask contains argon and oxygen in the ratio of 3:2 in mass and the mixture is kept at 27°C. The ratio of their average kinetic energy per molecule respectively will be :

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3 : 2

9 : 4

2 : 3

1 : 1

answer is D.

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Detailed Solution

Average K.E./molecule $= \frac{f}{2} kT$
So, $\frac{K_{Ar}}{K_{O_{2}}} = \frac{\frac{3}{2} kT}{\frac{5}{2} kT} = \frac{3}{5}$

If we consider only translational kinetic energy of a molecule, then $\frac{K_{Ar}}{K_{O_{2}}} = \frac{\frac{3}{2} kT}{\frac{3}{2} kT} = \frac{1}{1}$

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