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Q.

A flat plate moves normally towards a discharging jet of water at the rate of 3 m/s. The jet discharges the water at the rate of  0.1 m3/s  and at the speed of 18 m/s. The force exerted on the plate due to the jet, assuming after impact water moves along the plate, is

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a

2100 N

b

1560 N

c

1800 N

d

2450 N

answer is C.

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Detailed Solution

Relative velocity of the water jet with respect to the moving plate =  (18+3)ms1=21ms1

The mass hitting the plate per second =  aρ(21)

a  is cross-sectional area of the jet

F=MV=[aρ(21)](21)=441aρ

F=441×ρ×0.118   =441×0.1×100018=2450N

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A flat plate moves normally towards a discharging jet of water at the rate of 3 m/s. The jet discharges the water at the rate of  0.1 m3/s  and at the speed of 18 m/s. The force exerted on the plate due to the jet, assuming after impact water moves along the plate, is