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A flexible drive belt runs over a frictionless flywheel as shown. The mass per unit length of the drive belt is 1kg/m and the tension in the drive belt is 10N. The speed of the drive belt is 2m/s. The whole system is loaded on a horizontal plane. Find normal force (in N) exerted by the flywheel.

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answer is 12.

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Detailed Solution

$2 T - N = {mω}^{2} R_{cm} = μ \times πR \times {(\frac{V}{R})}^{2} \times \frac{2 R}{π}$

$2 T - N = 2 {μv}^{2}$

$N = 2 T - 2 {μv}^{2} = 2 \times 10 - 2 \times 1 \times 4 = 12 N$

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