A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm. How many such tiles are required to cover a floor of area 1080 $m^2$ ? (If required you can split the tiles in whatever way you want to fill up the corners).

Base of flooring tile = 24 cm = 0.24 m 

Corresponding height of a flooring tile= 10 cm = 0.10 m

Area of the flooring tile $= 0.24\times 0.10 = 0.024 m^2$

Area of the floor = 1080 $m^2$

∴ Number of tiles required $=\frac{Area of the floor }{Area of the flooring tile}=\frac{1080}{0.024}$= 45000 tiles