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A flywheel of moment of inertia $10 {kg m}^{2}$ is rotating at 50 rad/s. It must be brought to stop in 10 s. What is the required average power ?

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-250 W

-625 W

-1250 W

-2500 W

answer is C.

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Detailed Solution

$W = Δ Rotational kinetic energy$
$- \frac{1}{2} {Iω}^{2} = - \frac{1}{2} 10 (50^{2}) = - 12500 J$
$Average power = \bar{P} = \frac{W}{t} = \frac{- 12500}{10} = - 1250 W$

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