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Q.

A following mechanism has been proposed for a reaction:

2A+BD+EA+BC+D        (slow)A+CE              (fast)

The rate law expression for the reaction is

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a

r=k[A]2[B]

b

r = k[A][B]

c

r = k[A][C]

d

r = k[A]2

answer is B.

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Detailed Solution

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Slow step is

A + B  C + D (slow)

Hence, r = k[A][B]

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